Question

Plz answer these question with steps

Answer 1

2. CD|| ED and CF is transversal
<1 +130° = 180° (co. int. <s)
=<1 = 180°-130° = 50°
AB|| ED and AE is transversal
therefore <BAE + <AED =180 (co.int.<s)
= x° + 20° +<1 =180°
= x°+20°+50°=180°
=x° = 180-70° = 110°

1. BC|| ED and CD is transversal
therefore <1 +75=180 (co.int.<s)
<1=180-75=105
AB||CD and BC is transversal
therefore <1=x° (Alt. int.<s)
=105=x°
x=105

3. Given that l || m and t is transversal
(3x+5) +4x =180
7x+5 =180
x =175/7 X=25°