Question

plz answer these questions...​

Answer 1

Answer:

Q.27 :-

let the shorter side of rectangle be x m.

so, diagonal of rectangle= (x+60) m

and , longer side of rectangle = (x+30)m

now,

we know that ,

Diagonal of rectangle = √l^2+b^2

x+60 = √l^2+b^2

x+60= √(x+30)^2 + x^2

x+60=√x^2+900+60x + x^2

x+60=√2x^2+900 +60x

squaring on both sides

(x+60)^2=2x^2+60x+900

x^2+ 3600 + 120x = 2x^2+900+60x

2x^2-x^2+900-3600+60x-120x =0

x^2-60x-2700=0

x^2-90x+30x-2700=0

x(x-90) +30(x-90)=0

(x-90) (x+30)=0

x=90 or x= -30 . Ans....