Question

plz answer these questions. ​

Answer 1

Answer:

1). 62 + x = 180 ( angles on straight line)

x = 118

2) (3x-5) + (55)+(x + 20) =180 ( angles on a straight line)

4x + 70 = 180

4x = 110

x = 27.5

so angle AOC = 3x-5 = 3×27.5 - 5 = 77.5

angle BOD = x+20 = 27.5 +20 = 47.5

3). 3x +7 + 2x-19 + x = 180 ( angles on a straight line)

6x = 192

x= 32

angle BOD = x = 32

angle AOC = 3x+7= 3×32 +7= 103

angle COD = 2x -19 =2×32 -19 = 45

4). let take the ratio as 5a, 4a,6a

so 5a +6a +4a =180

15a = 180

a= 12

so x = 5a = 5×12 = 60

y = 4a=4×12=48

z= 6a =6×12=72

5). 3x+20+4x-36=180

7x-16=180

x=28

6) angleBOD = 50 ( vertically opposite angles)

angle AOD + 50 = 180 (angles on a straight line)

angle AOD = 130

angle AOD = Angle BOC = 130 ( vertically opposite angles)