Math, asked by nishu555, 11 months ago

plz answer these two questions guys. .............​

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Answered by darshan548
2

hope this will help u

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Answered by parashuramnalla
1

Answer:

27y^3 + 125z^3 =  ( 3y + 5z ) ( 9y^2 + 25z^2 - 15yz )

64m^  -  343n^3 =  ( 4m - 7n ) ( 16m^2 + 49n^2 + 28mn )

Step-by-step explanation:

27y^3 + 125z^3

= ( 3y )^3 + ( 5z )^3      [∵   a^3 + b^3 = ( a + b ) ( a^2 + b^2 - ab )

hence, a = 3y,   b = 5z

27y^3 + 125z^3 =  ( 3y + 5z ) ( 9y^2 + 25z^2 - 15yz )

64m^  -  343n^3

= ( 4m )^3 - ( 7n )^3      [∵   a^3 - b^3 = ( a - b ) ( a^2 + b^2 + ab )

hence, a = 4m,   b = 7n

64m^  -  343n^3 =  ( 4m - 7n ) ( 16m^2 + 49n^2 + 28mn )

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