Question

Plz answer these with calculations.

Answer 1

Step-by-step explanation:

1. <USQ=90°

<UST+<TSQ=90°

48+a=90

=>a=90-48

a =42°

<PQS+<SQR=180° (Linear pair)

=154+c=180

=>c=180-154

c=26°

<UST+<TSQ+<QSR=180° (straight line)

=>48+42+d=180

=>d=180-90

=d=90°

<SQR+<QSR+<SRQ=180°(sum of the interior

angles of a triangle).

=>26+90+b=180

=>b=180-110

b=70°

2. exterior angle = sum of two interior angle..

so...

=>25+x+15=3x-10

=>x-3x=-10-25-15

=>-2x=-50

=x=25

so....

3x-10

=3×25-10

=65

plzzzz mark brainliest and follow

Answer 2

Pls mark as brainliest answer