Question

plz answer this 2 question it's urgent​

Answer 1

Answer:

${(x + y)}^{3} - {(x - y)}^{3} - 6y( {x}^{2} - {y}^{2} ) = k {y}^{2} \\ (x + y - x + y)( {(x + y)}^{2} + {(x - y)}^{2} + (x + y)(x - y) - 6y( {x}^{2} - {y}^{2} ) = k {y}^{2} \\ (2y)( {x}^{2} + 2xy + {y}^{2} + {x}^{2} - 2xy + {y}^{2} + ( {x}^{2} - {y}^{2} ) - 6y( {x}^{2} - {y}^{2}) = k {y}^{2} \\ (2y)(2 {x}^{2} + 2 {y}^{2} + {x}^{2} - {y}^{2} ) - 6y {x}^{2} + 6 {y}^{3} = k {y}^{2} \\ 2y(3 {x}^{2} + {y}^{2} ) - 6y {x}^{2} + 6 {y}^{3} = k {y}^{2} \\ 6y {x}^{2} + 2 {y}^{3} - 6y {x}^{2} + 6 {y}^{3} = k {y}^{2} \\ 8 {y}^{3} = k {y}^{2} \\ 8 = k$

Answer 2

Answer:

the other one has done the first one ...so I'm going to do the 2nd question...