Math, asked by srishtikaur57, 5 months ago

plz answer this......​

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Answered by bshashank954
1

Answer:

Dimensions of the shelter

l=4m , b= 3m ,h= 2.5m

 

Required area of Tarpaulin to  make the shelter=

Area of four sides + area of  the top of the car

Tarpaulin required = 2(l+b)×h + lb

= [2(4+3)×2.5 + 4×3]

= (35+12)

= 47m²

Hence,Tarpaulin required to make the shelter=47m²

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Hope this will help you...

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