Question

plz answer this -- A 20m ladder is placed against the wall in such a way that the foot of the ladder is 16 cm away from the wall . how up on the wall is the upper end of the ladder . answer with full solution

(a). 20m
(b).12m
(c).18m
(d).24m

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Answer 1

Answer:

correct answer is b

draw a right triangle ABC and right angle at c

suppose ,

AB be ladder=20 m

and ,

BC be distance between foot of wall and foot of ladder = 16m

we find AC by pythagoras therom

(AC)2=(AB)2- (BC)2

PUT value

(AC)2=(20)2 - (16)2

(AC)2= 400 - 256

(AC)2= 144

AC = 12m

THANK U