Question

Plz answer this!!!!
A bullet of mass m moving horizontally with speed u strikes a block of mass M at rest and gets embedded in it as shown in figure. As a result, block starts moving and climbs along the smooth surface. What should be the minimum value of u so that the block reaches the topmost point shown in figure?

Answer 1

Answer:

The situation is as shown in the figure.

Let V be velocity of the block-bullet system just after collision. Then by the law of conservation of linear momentum, we get

mv=(m+M)V

V=

m+M

mv

Let the block rises to a height h.

According to law of conservation of mechanical energy,

we get

2

1

(m+M)V

2

=(m+M)gh

h= 2g

V 2

= 2gv 2

( m+M

m) 2

.

Explanation:

Please mark it as the "Brainliest".