Plz answer this as fast as possible!!!
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Hey you can solve it by this way as I have done
tan^3 theta - 1^3/tan theta - 1
= (tan theta - 1)(1 + tan^2 theta + tan theta)/tan theta - 1
=(1 + tan^2 theta)(tan theta)
=sec^2 theta + tan theta
tan^3 theta - 1^3/tan theta - 1
= (tan theta - 1)(1 + tan^2 theta + tan theta)/tan theta - 1
=(1 + tan^2 theta)(tan theta)
=sec^2 theta + tan theta
Anonymous:
Thnx for help!!!
do u have exam tommorrow
no
Well I have
okk
you of 10th class right
yeh
plz if your half yearly exam of maths is over can u send me the photographs
kk
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