plz answer this.......asap......
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Case 1)
Distance travelled(s1)=200 m
Speed=40 m/min
so,
time taken(t1)=distance/speed=5 min
........
Average speed=100 m/min
since,
average speed=total distance/total time
100=1000/(t1+t2)
t1+t2=10 min
So, t2=10-5=5 mins
so,
Mans have to cover 800 m in 5 mins
so, speed=800/5=160 m/min
Distance travelled(s1)=200 m
Speed=40 m/min
so,
time taken(t1)=distance/speed=5 min
........
Average speed=100 m/min
since,
average speed=total distance/total time
100=1000/(t1+t2)
t1+t2=10 min
So, t2=10-5=5 mins
so,
Mans have to cover 800 m in 5 mins
so, speed=800/5=160 m/min
manu1121:
ur right
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