Question

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Answer 1

Answer:

10

Step-by-step explanation:

angle BCE = angle BCD+ angle DCE

= 70+60= 130

BC= CE ( since DCE is s equilateral triangle and ABCD is a rhombus)

so angle CBE+ angle CED = 180-130= 50

and triangle BCE is a isosceles as I said above

so angle CEB = 50/2= 25

the adjacent angles in a rhombus are add up-to 180 since it will follow parallelogram properties

so angle ABC = 180-70=110

so angle ABE = 110-25= 85

same way angle BAE =85

so angle AEB = 180-85-85= 10

if you don't understand let me know I will draw the figure and explain