Question

plz answer this buddy....​

Answer 1

Hey buddy here is ur answer =

here we will use common potential difference.

so let's find the charge =

parameters given are =

c1=1

c2=3

c3=6

so let's find charge

Q= c1 × v

Q= 60 mv

now we will find v

60= v × ( c1 + c2×c3/c2+c3)

60= v × (1 + 18/9)

60 = v × 3

v= 20 v

now charge on c2 and c3 =

formula = ( c2×c3/c2+c3) × v

= ( 18/9) × 20

= 2 × 20

=40 mv

hope now ur doubt is clear ....

happy to help :-)

Answer 2

Answer:

Explanation:

solet'sfindthecharge=

parametersgivenare=

c1=1

c2=3

c3=6

solet'sfindcharge

Q=c1×v

Q=60 mv

nowwewillfind v

60=v×(c1+c2×c3/c2+c3)

60=v×(1+18/9)

60=v×3

v=20v

nowchargeonc2andc3=

formula=(c2×c3/c2+c3)×v

=(18/9)×20

=2×20

=40mv

Hope it will help u