pLz answer this
class 8th
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EXPLANATION:-
- Step 1:- We can write 16 as (4)^2 and 8 as (2)^-3
- Step 2:- We know that we need to substract in divide and addition in multiply so we are substracting (4)^2 and (4)^-3 together
- In the next step we have to change the (4)^7 as (2)^2*7 and we get (2)^14
- Next as earlier explained we have to substract (2)^14-3 and we get (2)^11
ANSWER WE GET AT LAST IS (2)^11*(t)^4
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