Question

plz answer this correctly with steps​

Answer 1

Step-by-step explanation:

in ∆ ABD and ∆ ACD

angle ADB = angle ADC = 90° [ given ]

BD = CD [ AD bisects BC given ]

AD = AD [ common side ]

by SAS criteria, ∆ ABD congruent ∆ ADC

therefore by CPCT, AB = AC

hence proved

[ CPCT = corresponding parts of congruent ∆ are equal ]

Answer 2

Given :-

AB = AC

To,

Prove that ABC tis an isosceles triangle.

Solution :-

In $\triangle$ ABD and $\triangle$ ACD

= AB = AC (given)

= AD = AD (common)

= $\angle$ ADB = $\angle$ ADC (each 90°)

$\therefore$ Triangle ABD is congurent to Traingle ACD (SAS congurance rule)

So,

ABC is an isosceles triangle (CPCT)

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