Question

Plz answer this... Discuss the continuity on its domain.

Answer 1

Hey Mate

Your answer is here

Given that domain of function is [ 0 , 6 ]

And we can see that function only change on x = 4 ,

So,,,

We need to check continuity at x = 4 only.

For x < 4

We have

f(4) = ( 16 - 12 + 2 )/ ( 4 - 3 )

f (4) = 6

And for x > 4

We have

f(4) = ( 16 + 1 )/(4 - 2 )

f(4) = 17/2

Bcoz 6 is not equal to 17/2

So,,,

Given function is discontinues at x = 4

Thanks,,,,,

Plz mark as brainiest.