Question

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Answer 1

Step-by-step explanation:

In the given figure there are three right triangle.

so, firstly, obtain all things we can obtain.

so,In ∆ ABC , AB² + BC² = AC²

i.e . c² + BC² = (e+d)²

BC ² = (e+d)² -c²

In ∆ ABD ,

e² + BD² = c²

BD² = c²- e²

and ,In ∆ BCD ,

BD² +d² = BC².........(1)

putting the value of BD and BC in (1)

then, c² -e² +d² = (e+d)² -c²

hence, 2c²+d² = e² +d² +2ed +e²

2c² = 2e² + 2ed = 2(e²+ed)

so, e² +ed = c²