Question

plz answer this
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Answer 1

Answer:

answer is 8.......

sry i dont the steps by steps

Answer 2

Step-by-step explanation:

Given chords AB=6 cm, OL = 4cm cm and AB|| OL

Draw OP⊥ AB.

Let it intersect OL at Q and AB at P ∴ AP = PB = 3 cm and CQ = DQ = 6 cm [Since perpendicular draw from the centre of the chord bisects the chord]

Let OD = OB = r

In right ΔOQD, r^2 = x^2 + 6^2 [By Pythagoras theorem] r^2 = x^2 + 36 → (1)

In right ΔOPB, r^2 = (x + 3)^2 + 3^2 [By Pythagoras theorem] Þ

r^2 = x^2+ 6x + 9 + 9 = x^2 + 6x + 18 → (2)

From (1) and (2)

we get x^2 + 36 = x^2 + 6x + 18

⇒ 6x = 18 ∴ x = 3

Put x = 3 in (1), we get r^2 = 3^2 + 36 = 9 + 36 = 45 ∴ r = √45 = 5 cm

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