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Answer:
Required angle = 50°
Step-by-step explanation:
Given in image.
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Answer:
in ∆OAB,
OA=OB [ radii of some circle]
angle OBA=angle OAB=40° { angle S opp. to equal side in a ∆ are equal}
Now, angle OAB+angleAOB+angleOBA=180° ( angle sum property of a ∆)
=40°+ angleAOB+ 40°=180°
=angleAOB=100°
Therefore, angleACB=50° [ angle subtended by an arc at the centre is double the angle substended by it at the remaining part of a circle]
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