Question

plz answer this fast​

Answer 1

Hey...

Here is your answer

Hope it helps

Answer 2

Diagram regards question:

$\setlength{\unitlength}{1mm}\begin{picture}(7,2)\thicklines\multiput(7,2)(1,0){55}{\line(3,4){2}}\multiput(35,7)(0,4){12}{\line(0,1){0.5}}\put(10.5,6){\line(3,0){50}}\put(35,60){\circle*{12}}\put(37,7){\large\sf{v = 49 m/s}}\put(37,55){\large\sf{u = 0 m/s}}\put(21,61){\textsf{\textbf{Body}}}\put(43,40){\line(0, - 4){28}}\put(43,34){\vector(4){18}} {\pmb{\sf{BrainlyButterfliee}}}\put(24, - 3){\large\sf{ \sf g = 9.8 m/s^2 }}\put(48,30){\large\sf{H = ?}}\end{picture}$

Provided that:

• Initial velocity = 0 mps
• Final velocity = 49 mps
• g = 9.8 mps sq.

Don't be confused!

Initial velocity cames as 0 mps because the body is dropped from a height.

To calculate:

• Height of tower

Solution:

• Height of tower = 122.5 m

Using concept:

• Third equation of motion

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{v^2 \: - u^2 \: = 2gs}}}}}}$

Where, v denotes final velocity, u denotes initial velocity, g denotes acceleration due to gravity and s denotes displacement or distance or height.

Required solution:

~ Let's find out the height of the tower by using third equation of motion.

→ v² - u² = 2gs

→ (49)² - (0)² = 2(9.8)(s)

→ 2401 - 0 = 19.6s

→ 2401 = 19.6s

→ 2401/19.6 = s

→ 122.5 = s

→ s = 122.5 m

→ Height = 122.5 m

Additional information:

There are three equations of motion that are mentioned below:

(1) v = u + at

(2) s = ut + ½ at²

(3) v² - u² = 2as

Where, a denotes acceleration, u denotes initial velocity, v denotes final velocity, s denotes displacement or distance and t denotes the time taken.