Question

Plz answer this fast I need it urgently ... plz ... I will mark as brainliest.... plz answer .. please plz

Answer 1

Answer:

Let the two digits be x and y.

According to the question,

$x + y = 7$

$10y + x = \frac{1}{2} (10x + y) - 1$

Note: Here the original number is 10x+y

Now from the first equation,

$x = 7 - y$

Putting the value in second equation,

$10y + 7 - y = \frac{1}{2} (10(7 - y) + y) - 1$

$9y + 7 = \frac{1}{2} (70 - 10y + y) - 1$

$9y + 7 = \frac{1}{2} (70 - 9y) - 1$

$2(9y + 8 ) = 70 - 9y$

$18y + 16 = 70 - 9y$

$27y = 54$

$y = 2$

$x = 7 - y = 7 - 2 = 5$

Therefore, the original number is 10x+y= 52