plz answer this fast...no10
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110 IT SHOULD BE 11O FIRST FIND OUT THE BAE THEN THE VALUE OF x
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Draw EF||AB||CD.
DCB+CEF=180
=>130+CEF=180
CEF=50
AB||EF and AE Transversal.
BAE+AEF=180
=> x+(20+50)=180
=180-70=110
DCB+CEF=180
=>130+CEF=180
CEF=50
AB||EF and AE Transversal.
BAE+AEF=180
=> x+(20+50)=180
=180-70=110
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