Plz answer this
Given a three digit number x5y where x is the digit at hundreds place and y is the digit at units place. If the number x5y is divisible by 9, find the least positive value of x+y.....
Is the answer 9???
plz send the solution also, or if the answer is something else plz send the solution also
nicki1362:
sorry the answer is 4
Answers
Answered by
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no... the answer is 4...
if the no. x5y is divisible by 9, x+5+y>=9
since we want the least value, we take it as
x+5+y=9
x+y=4
if the no. x5y is divisible by 9, x+5+y>=9
since we want the least value, we take it as
x+5+y=9
x+y=4
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