Question

plz answer this help​

Answer 1

x = 2^(1/3) - 2^(-1/3)

= 2^(1/3) - 1/2^(1/3)

= (2^(2/3) -1)/2^(1/3)

therefore, 2x^3 + 6x

= 2 [2x^(2/3) -1]^3 + 6(2^(2/3) -1)/2^(1/3)

= 2^2 -1 -3*2^(2/3)(2^(2/3) -1) + 6*2^(2/3)(2^(2/3) -1)

= 3 - 3 * 2 ^(4/3) + 3*2^(2/3) + 3*2^(2/3)(2^(2/3)-1)

= 3 - 3*2*2^(1/3) + 3*2^(2/3) + 3*2*2^(1/3) - 3*2^(2/3)

= 3

Hope that helps.

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Karthikrikky12 ♥️