Chemistry, asked by Aru18angrybird, 1 year ago

plz answer this.......
how can we obtain copper sulphate crystals from a mixture of charcoal and black copper oxide.
show the reaction with the help of an equation.

Answers

Answered by Anonymous
3

Answer:

The carbon in the charcoal reduces the black copper oxide to reddish-brown copper. The lid must not be removed until the crucible is cool or the hot copper will be re-oxidized by air. Take dilute sulphuric acid in a beaker and heat it on wire gauze. Add cupric oxide in small quantities at a time, with stirring till no more of it dissolves and the excess compound settles to the bottom. Filter it hot and collect the filtrate in china dish. Evaporate the filtrate by heating to the point of crystallization and then allow it to cool and collect the crystals of copper sulphate

penta-hydrate. Reaction: CuO + H2SO4 ⟶ CuSO4 + H2O CuSO4 + 5H2O ⟶ CuSO4. 5H2O

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