plz answer this...it's urgent...
I'll definitely mark u brainliest if u are able to explain me that why the 2nd option has higher molar conductivity and what's the concept to find it out...
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Answered by
1
since so4 is ionic bonds I.E. polar covalent bond and other are covalent bonds
how you mark me brainliest this is the correct answer
how you mark me brainliest this is the correct answer
this is what I read somewhere that I told
in 2015 MRIP mock test series question papers
okay
so what is the answer final according to you jinakhazma
I think it is Option 2) but I have still doubt cause I didn't read Electrochemistry.
Answered by
7
Since, I didn't read much about Electrochemistry, therefore there may be error in the understanding which I followed from my own opinion.
Molar conductivity of a solution depends degree of dissociation of that compound in aquous solution.
(According to NCERT)
So,
We know that
1)
In first case, If we dissociate the CO ordination complex, then it will give Br-.
Then, that Br-will try to form HBr by obtaining H+ from water which is too Unstable compound as Bond strength is weaker in HBr and hence easily breaks.
Thus, Formed compound will not be much stable.
2) Here, Counter ion is SO4)2- which after getting dissociated from Co ordination complex, it easily forms H2 SO 4 compound which is much more stable than HBr and other der]vaties of these option.s
3) Here,
Counter anion is NO2)-
If this Co ordination compound gets dissociated then, NO2)- will came and it will react with H water or H + from it to become HNO2 which is too unstable as oxidation number of N is 3 which is unstable.
4) Since, Option is impossible as
this complex can't be broken into its ions form as it contains water of crystallization which is constant and H2O is happy in that form.
We cant dissociate but Whole water molecule may get removed to left anhydrous Co ordination complex.
That, Complex will not show any molecular conductivity in aqueous medium.
Hope, you understand my answer .
----------------
Molar conductivity of a solution depends degree of dissociation of that compound in aquous solution.
(According to NCERT)
So,
We know that
1)
In first case, If we dissociate the CO ordination complex, then it will give Br-.
Then, that Br-will try to form HBr by obtaining H+ from water which is too Unstable compound as Bond strength is weaker in HBr and hence easily breaks.
Thus, Formed compound will not be much stable.
2) Here, Counter ion is SO4)2- which after getting dissociated from Co ordination complex, it easily forms H2 SO 4 compound which is much more stable than HBr and other der]vaties of these option.s
3) Here,
Counter anion is NO2)-
If this Co ordination compound gets dissociated then, NO2)- will came and it will react with H water or H + from it to become HNO2 which is too unstable as oxidation number of N is 3 which is unstable.
4) Since, Option is impossible as
this complex can't be broken into its ions form as it contains water of crystallization which is constant and H2O is happy in that form.
We cant dissociate but Whole water molecule may get removed to left anhydrous Co ordination complex.
That, Complex will not show any molecular conductivity in aqueous medium.
Hope, you understand my answer .
----------------
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