Question

Plz answer this it's urgent
Plzz

Answer 1

Hello friend, Harish here

Here is  your answer: (REFER TO THE IMAGE)

Hope my answer is helpful to you.

Answer 2

By formula, a³-b³=(a-b) (a²+ab+b²)

$(x + y - ( x - y)) \times ((x + y)^{2} + (x + y)(x - y) + ( x - y)^{2} ) - 6y( {x}^{2} - {y}^{2} ) = k {y}^{2} \\ \\ \\ \\ (x + y - x + y) \times (x ^{2} + {y}^{2} + 2xy + {x}^{2} - {y}^{2} + {x }^{2} + {y}^{2} - 2xy) - 6y( {x}^{2} - {y}^{2} ) = {ky}^{2} \\ \\ \\ (2y) \times ( {3x }^{2} + {y}^{2} ) - 6y( {x}^{2} - {y}^{2} ) = {ky}^{2} \\ \\ 2y( {3x}^{2} + {y}^{2} - 3 {x}^{2} + 3 {y}^{2} ) = {ky}^{2} \\ \\ 2(4 {y}^{2} ) = ky \\ \\ 8 {y}^{2} = ky \\ \\ \frac{8 {y}^{2} }{y} = k \\ \\ \\ 8y = k$



I hope this will help you

-by ABHAY