Physics, asked by rutanshpandya906, 5 hours ago

PLZ ANSWER THIS ITS PYQ I REQ​

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Answered by Thekaleb
0

Answer:

5%

Density = (2+- 0.1) kg/m^3

Explanation:

First calculate the percentage error of the three quantities given

% error of mass = (0.1/10)*100% = 1%

% error of radius = (0.01/1)*100% = 1%

% error of height = (0.1/5)*100% = 2%

Density = m/r^2*h

So % error of density = %m + 2(%r) + %h

= 1%+ 2(1%) + 2%

= 5%

Density = m/r^2*h

= 10/1^2 * 5

= 10/5

= 2kg/m^3

Error of density = %D * Density

= 5% * 2kg/m^3

= 0.1 kg/m^3

Density =(2 +or- 0.1) kg/m^3

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