Question

Plz answer this<br />Given a three digit number x5y where x is the digit at hundreds place and y is the digit at units place. If the number x5y is divisible by 9, find the least positive value of x+y...

Is the answer 4???
if the answer is something else plz send the solution also

Answer 1

by divisibility test of 9 sum of digits must be divisible by 9
hence x+y+5=y
where y is a real number
minimum value of y possible is 9
hence
x+y+5=9
x+y=4