plz answer this one....I'm unable to do that
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Let √20+√20+.... be x
√20+x=x
squaring both sides,
x²=20+x
x²-x-20=0
x²-5x+4x-20=0
x(x-5)+4(x-5)=0
(x-5)(x+4)=0
so if x²-5x-20 = 0
either (x-5)=0 or (x+4)=0
x-5=0
x=5
or,
x+4=0
x=-4
Thus,
roots of following equation are : 5 , -4
Hope , this help!
√20+x=x
squaring both sides,
x²=20+x
x²-x-20=0
x²-5x+4x-20=0
x(x-5)+4(x-5)=0
(x-5)(x+4)=0
so if x²-5x-20 = 0
either (x-5)=0 or (x+4)=0
x-5=0
x=5
or,
x+4=0
x=-4
Thus,
roots of following equation are : 5 , -4
Hope , this help!
Answered by
0
hope it helps...
pls see the attachment
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