Question

plz answer....this one.....very important.....10th question.....​

Answer 1

Answer:

x = 2 or x = -2

Explanation:

let multiply each term in the given equation by x,

${x}^{2} - 1 = 3 \\ {x}^{2} - 1 - 3 = 0 \\ {x}^{2} - 4 = 0 \\ (x + 2)(x - 2) = 0 \\ x + 2 = 0 \: \: or \: \: \: \: x - 2 = 0 \\ x = - 2 \: \: \: or \: \: \: x = 2$

here the identity used is

a^2 -b^2 = (a+b) (a-b)

Answer 2

hi mate ur answer.....

let the equation be y...

2

X - 1=0

2

X -1-3=0

2

X -4=0

(x-2) (x+2)=0

x =-2.. x=2

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