plz answer this plz
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given is abcd is a parrelogram eand f are the mid pt of side ab and CD resp.
to show that line segment af and ec trisect the diagonal bd.
abcd is a parallelogram.
therefore ab prallel to CD.
also ae equal to CD (opp side of parallelogram are equal)
half ab=half CD
fcequal to ae
so aecf is a parallelogram
now
in triangle doc,
f is a mid pt of side dc and ep
so P is a mid pt of dq
by convers of mpt th
dp equal to pq mark point1
similarly
in triangle apb
e is the mid pt of ab and eq.
so that q is the mid pt of pb
pq equal to qb mark it point2,
from point 1and 2
hence proved
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