Question

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Answer 1

Answer: 1/$R_{eq}$ = 1/R₁ + 1/R₂

Explanation:

When resistors are connected in parallel ,V is same everywhere.

From Ohm's law,   V = IR

I = I₁ + I₂

V/$R_{eq}$ = V/R₁ + V/R₂

V(1/$R_{eq}$) = V(1/R₁ + 1/R₂)

1/$R_{eq}$ = 1/R₁ + 1/R₂

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Answer 2

Answer:

Let us consider two resistors R¹ and R² connected in parallel .These two reasistors are connected to a battery for which they have same potential difference(V). I¹ and I² are the amount of current flowing through the two resistor R¹ and R² respectively as shown in figure above .

let R be effective resistor and I be the current flowing through the circuit.

Now according to ohm's law we have

I = V/R

I¹ = V/R¹

I²= V/R²

now I = I¹ + I²

so V/R = V/R¹ + V/R²

so 1/R = 1/R¹ + 1/R²

This is the expression for effective resistance of two resistor connected in parallel.