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a vehicle of 1 tonne travelling with a speed of 60m/s notices a cow on the road 9 m ahead applies brakes. it stops just in front of the cow .
1.find out the kinetic energy of the vehicle before applying brakes
2. calculate the retarding force provided by the brakes.
- So kinetic energy before applying brake will be.
- K.E = 1/2 mv^2
- = 1/2 × 10^3 × 60^2
- = 1/8 × 10^6 J
- We know that from equation of motion we get
- So v^2 = u^2 + 2as
- 0 = 60^2 + 2a(9)
- 0 = 3600 + 18a
- Or a = -200m/s^2
- Now regarding Force F = ma
- = 10^3 × 200
- Or Force F = 2 × 10^5 N
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