plz answer this q from rationalizing the denominator
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here is your answer.
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Given
x=5-2root6----(1)
1/x= 1/(5-2root6)
=(5+2root6)/5-2root6)(5+2root6)
=(5+2root6)/(25-24)
=5+2root6----(2)
x+1/x= 5-2root6+5+2root6 (from(1)and(2))
=10---(3)
Square(3) bothsides
(x+1/x)^2=(10)^2
x^2+1/x^2+2×x×1/x =100
x^2+1/x^2=100-2=98
x=5-2root6----(1)
1/x= 1/(5-2root6)
=(5+2root6)/5-2root6)(5+2root6)
=(5+2root6)/(25-24)
=5+2root6----(2)
x+1/x= 5-2root6+5+2root6 (from(1)and(2))
=10---(3)
Square(3) bothsides
(x+1/x)^2=(10)^2
x^2+1/x^2+2×x×1/x =100
x^2+1/x^2=100-2=98
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