Math, asked by devanshjain588p8nlwm, 1 year ago

plz answer this Q7............

Attachments:

Answers

Answered by skh2
1
Hello,

Nice question......
We can solve this by using identities.

The identities to be used are:-
 {(x + y)}^{2}  =  {x}^{2}  +  {y}^{2}  + 2xy
 {x}^{3}  +  {y}^{3}  = (x + y)( {x}^{2}   - xy +  {y}^{2} )

Now, first of all we have been given..
a + b = 8 \\  {a}^{2}  +  {b}^{2}  = 85
Using 1st identity

 {(a + b)}^{2}  =  {a}^{2}  +  {b}^{2}  + 2ab \\  {8}^{2}  = 85 + 2ab \\ or \:  \: 2ab = 64 - 85 =  - 21 \\ ab =  \frac{ - 21}{2}  =  - 10.5

Now, using 2nd identity :-

 {a}^{3}  +  {b}^{3}  = (a + b)( {a}^{2}  - ab +  {b}^{2} ) \\ {a}^{3}  +  {b}^{3} = 8 \times (85 - ( \frac{ - 21}{2} ) \\ {a}^{3}  +  {b}^{3} \:  = 8 \times  \frac{191}{2}  = 4 \times 191 = 764

Hope this will be helping you ✌️ ✌️
Similar questions