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hi dear
molar mass of Nacl = 23 + 35.5 = 58.5 g
no of moles = 5.85/58.5 = 0.1 mole
concentration /molarity = no of moles / volume in litres
= 0.1/1 = 0.1 M
molar mass of Nacl = 23 + 35.5 = 58.5 g
no of moles = 5.85/58.5 = 0.1 mole
concentration /molarity = no of moles / volume in litres
= 0.1/1 = 0.1 M
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