Question

plz answer this ques from my math book

Answer 1

(a) Principal=1200 rupees(P)
Rate of interest=12percent per annum(R)
Time=3 yrs(T)
Simple interest=P×R×T÷100
1200×12×3÷100
=432 rupees

(b)Principal=7500 rupees(P)
Rate of interest=5 percent per annum(R)
Time=3yrs
Simple interest=P×R×T÷100
7500×5×3÷100
=1125 rupees

Answer 2

if simple intrest then

p=Rs1200

Rate 12%

Time =3 Years

∴ SI=(P×T×R)÷100

∴SI=(1200×3×12)÷100

SI=43200÷100

SI=RS 432

Amount =P+SI=1200+432=RS 1632 ANS FOR SIMPLE INTEREST

if compound intrest then

Amount =P[1+(rate/100)^n]

Amount =1200[1+(12/100)^3]

Amount =1200[(100+12)/100]^3

Amount =1200[(112)/100]^3

Amount =1200×[112/100]×[112/100]×[112/100]

Amount =16859136/10000

Amount =RS 1685.91 ANS FOR COMPOUND INTEREST

For Question b do the same process as shown for question a

∴