Question

plz answer this question​

Answer 1

Answer:

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Answer 2

here ,

given that angle BEC = 90° .

then angle AEB = 90° ( by linear pair )

similarly , angle BFC is 90°

so angle AFC will also be 90°

Now , in ∆ ABE & ∆ ACF

angle A = angle A ( common angle )

angle AEB = angle AFC ( both 90° )

FC = EB ( given )

by AAS congruence , we can say that ∆ ABE is congruent to ∆ ACF

and by c.p.c.t. ,

AB=AC

so ∆ ABC is isosceles .

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