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2.here sinx= 3/4 so cosecx=4/5
similarly cosx=√7/4 and secx=4/√7
tanx=3/√7 and cotx=√7/3
cos²x- cot²x=(4/3)²-(√7/3)²
=16/9-7/9
=1
sec²x-1= tan²x
=9/7
√ ( cosec²x - cot² x)/ sec² x-1)=√7/9
=√7/3
answer is √7/3
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