plz answer this question
Attachments:
Answers
Answered by
1
0 is your answer of the question
Answered by
0
(4x^2-4)/8 (x^2+x-2)
=4(x^2-1)/8(x^2-x+2x-2)
=[(x+1)(x-1)]/2[x(x-1)+2(x-1)]
=[(x+1)(x-1)]/2(x-1)(x+2)
=(x+1)/2(x+2)
=4(x^2-1)/8(x^2-x+2x-2)
=[(x+1)(x-1)]/2[x(x-1)+2(x-1)]
=[(x+1)(x-1)]/2(x-1)(x+2)
=(x+1)/2(x+2)
Similar questions