Question

plz answer this question ​

Answer 1

Answer:

Identities used:-)

$log_{x}(x) = 1 \\ \\ log_{ {x}^{y} }( {m}^{n} ) = \frac{n}{y } \times log_{x}(m)$

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Firstly on solving LHS we will get a constant and then we will find value of x.

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Given expression can be solved for x using above identities as:-)

$log_{9}(27) = 2x + 3 \\ \\ log_{ {3}^{2} }( {3}^{3} ) = 2x + 3 \\ \\ \frac{3}{2} log_{3}3 = 2x +3 \\ \\ \frac{3}{2} \times 1 = 2x + 3 \\ \\ \frac{3}{2} = 2x + 3 \\ \\ 2x = \frac{3}{2} - 3 \\ \\ 2x = - \frac{ 3}{2} \\ \\ x = - \frac{3}{4}$