Question

plz answer this question ​

Answer 1

Step-by-step explanation:

in∆ADB

using Pythagoras theorem

9x^2 + 16x^2 = 100

25x^2 = 100

x^2 = 4

X = 2

so

both side is 6 and 8 respectively

since One angle is 90 of parallelogram so

it is rectangular parallelogram

whose perimeter = 2(L + B)

perimeter = sum of all side = 2( 6 + 8) = 2*14= 28

Answer 2

Question :-----

• Sides of llgm
• perimeter of parellogram .

Given :-----

• Ratio of adjacent sides of llgm = 3:4
• angle A = 90°
• Diagonal BD = 10cm

Formula used :------

• Pythagoras theoram say that, (Hpyotenuse)² = Base² + perpendicular² (in right ∆)
• Perimeter of llgm = 2(sum of adjacent sides)
• Opposite sides of llgm are Equal .

Solution :------

Let adjacent sides of ll AD and AB be = 3x and 4x ..

since ∆ DAB is Right angled ∆ , right angle at A.

By Pythagoras theoram , we get,

BD² = AD² + AB²

Putting values we get,

$BD^{2} = (3x)^{2} + {(4x)}^{2} \\ \\ ( {10)}^{2} = 9 {x}^{2} + 16 {x}^{2} \\ \\ 100 = 25 {x}^{2} \\ \\ {x}^{2} = \frac{100}{25} = 4 \\ \\ x = 2$

So , adjacent sides of ll gm are :----

AD = 3x = 3×2 = 6cm

AB = 4x = 4×2 = 8cm

so,

CB = AD = 6cm

DC = AB = 8cm

so, perimeter of llgm = 2(AB+AD) = 2(6+8) = 2×14 = 28cm..

(Hope it helps you)