Question

plz answer this question ​

Answer 1

Step-by-step explanation:

From ∆CDP and ∆ABQ

DC=AB

Angle P =Angle Q {each 90°}

PQ=PQ ( common)

Both the triangles are congruent, by SAS

By CPCT, DP=BQ

From ∆ADP & ∆CBQ

AD=BC(sides of rectangle are equal.)

DP=BQ(Above proved)

AP=CQ

Both triangles are congruent, By SSS

By CPCT, Angle ADP=Angle CBQ

MARK AS BRAINLIEST UF HELPFUL.

Answer 2

Answer:

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from triangle CDP and triangle ABQ

DC = AB

Angle B = angle Q ( each 90°)

PQ=PQ( Common)

both triangle are congruent by CPCT