Question

plz answer this question ​

Answer 1

Step-by-step explanation:

Given :

m sinθ = n cosθ

⇒ tanθ = (n/m)

⇒ cotθ = (1/tanθ) = (m/n)

Now,

(i)

(tanθ + cotθ)/(tanθ - cotθ)

⇒ (n/m + m/n)/(n/m - m/n)

⇒ (n² + m²/mn)/(n² - m²/mn)

⇒ (n² + m²/n² - m²)

(ii)

(n sinθ + m cosθ)/(n sinθ - m cosθ)

divide numerator and denominator by cosθ, we get

⇒ (n tanθ + m)/(n tanθ - m)

⇒ [n(n/m) + m]/[n(n/m) - m]

⇒ [(n² + m²/m)]/[(n² - m²/m)]

⇒ (n² + m²)/(n² - m²)

Hope it helps!

Answer 2

Answer:

refer to the above attachment for the solution