plz answer this question...
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Here is your answer mate:
(y + 1)/3 - (y - 1)/2 = (1 + 2y)/3
[2(y + 1) - 3(y - 1)]/6 = (1 + 2y)/3
[2y + 2 -3y + 3]6 = (1 + 2y)/3
(5 - y)6 = (1 + 2y)/3
5 - y = 2(1 + 2y)
5 - y = 2 + 4y
5 - 2 = 4y + y
3 = 5y
y = 3/5
hope this answer helps you buddy
please mark as brainliest:-)
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