Math, asked by priyankasingh790, 11 months ago

plz answer this question...​

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Answered by gayathriraja2002
1

Here is your answer mate:

(y + 1)/3 - (y - 1)/2 = (1 + 2y)/3

[2(y + 1) - 3(y - 1)]/6 = (1 + 2y)/3

[2y + 2 -3y + 3]6 = (1 + 2y)/3

(5 - y)6 = (1 + 2y)/3

5 - y = 2(1 + 2y)

5 - y = 2 + 4y

5 - 2 = 4y + y

3 = 5y

y = 3/5

hope this answer helps you buddy

please mark as brainliest:-)

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