Question

plz answer this question !!!​

Answer 1

$\begin {aligned}&\dfrac {7\sqrt 3}{\sqrt {10}+\sqrt 3}-\dfrac {2\sqrt 5}{\sqrt 6+\sqrt 5}-\dfrac {3\sqrt 2}{\sqrt {15}+3\sqrt 2}\\\\\\=\ \ &\dfrac {7\sqrt 3(\sqrt {10}-\sqrt 3)}{(\sqrt {10}+\sqrt 3)(\sqrt {10}-\sqrt 3)}-\dfrac {2\sqrt 5(\sqrt 6-\sqrt 5)}{(\sqrt 6+\sqrt 5)(\sqrt 6-\sqrt 5)}-\dfrac {3\sqrt 2(\sqrt {15}-3\sqrt 2)}{(\sqrt {15}+3\sqrt 2)(\sqrt {15}-3\sqrt 2)}\\\\\\=\ \ &\dfrac {7\sqrt 3(\sqrt {10}-\sqrt 3)}{10-3}-\dfrac {2\sqrt 5(\sqrt 6-\sqrt 5)}{6-5}-\dfrac {3\sqrt 2(\sqrt {15}-3\sqrt 2)}{15-18}\end {aligned}$

$=\dfrac {7\sqrt 3(\sqrt {10}-\sqrt 3)}{7}-2\sqrt 5(\sqrt 6-\sqrt 5)-\dfrac {3\sqrt 2(\sqrt {15}-3\sqrt 2)}{-3}\\\\\\=\sqrt 3(\sqrt {10}-\sqrt 3)-2\sqrt 5(\sqrt 6-\sqrt 5)+\sqrt 2(\sqrt {15}-3\sqrt 2)\\\\\\=\sqrt{30}-3-2\sqrt {30}+2\times5+\sqrt {30}-3\times2\\\\\\=-3+10-6\\\\=\Large\textbf{1}$

Answer 2

Answer:

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