Question

plz answer this question.​

Answer 1

SoluTion :-

$\frac{1}{x-2} + \frac{2}{x-1} = \frac{6}{x}\\\\\frac{x-1+2x-4}{(x-2)(x-1)} = \frac{6}{x}\\\\\\ x(3x - 5) = 6(x-2)(x-1)\\\\3x^2 - 5x = 6 (x^2 - x - 2x +2\\\\3x^2 - 5x = 6 x^2 - 18x +12\\\\13x^2 - 3x^2 - 12 = 0\\\\3x^2 - 13x + 12 = 0\\\\3x^2 - 4x -9x + 12 = 0\\\\(3x-4)(x-3)=0\\\\3x-4=0\\\\3x=4\\\\x=\frac{4}{3} \\\\x-3=0\\\\x=3\\\\x=3\\\\\ or\ \frac{4}{3}$

$\rule {130}{2}\ Be \ Brainly \ \star$

Answer 2

Answer:

So x = 3 , 4 / 3

Step-by-step explanation:

We Have :-

$\frac{1}{x-2}+\frac{2}{x-1}=\frac{6}{x}$

To Find :-

x

Solution :-

$\frac{1}{x-2}+\frac{2}{x-1}=\frac{6}{x}$

$\frac{x-1+2(x-2)}{(x-2)(x-1)}=\frac{6}{x} \\\\\frac{x-1+2x-4}{x^{2}-x-2x+2} =\frac{6}{x}$

$\\\frac{3x-5}{x^{2}-3x+2}=\frac{6}{x} \\\\x(3x-5)=6(x^{2}-3x+2)\\\\3x^{2}-5x=6x^{2}-18x+12\\\\3x^{2}-5x-6x^{2}+18x-12=0\\\\-3x^{2}+13x-12=0\\\\3x^{2}-13x+12=0\\\\3x^{2}-9x-4x+12=0\\\\3x(x-3)-4(x-3)=0\\\\(3x-4)(x-3)=0\\\\x-3=0\\\\x=3\\\\3x-4=0\\\\3x=4\\\\x=\frac{4}{3}$

So x = 3 , 4 / 3