Question

plz answer this question ​

Answer 1

Answer:

Given:

5C located at (6,8) and 2C at (3,4).

To find:

Electrostatic Force between the force

Concept:

Apply formula of Coordinate Geometry to obtain the distance between the Charges. Then use usual formulas to calculate force.

1/(4πε) is a constant introduced while making the equality between force and product of charges and distance.

ε is known as the Permittivity of Free space. It actually gives an index of capability of field lines to permeate a particular medium or vacuum.

Calculation:

Let distance be d

$d = \sqrt{ {(6 - 3)}^{2} + {(8 - 4)}^{2} }$

$= > d = \sqrt{ {3 }^{2} + {4}^{2} }$

$= > d = \sqrt{9 + 16}$

$= > d = \sqrt{25}$

$= > d = 5 \: metres$

Now , force be f ;

$f = \dfrac{1}{4\pi \epsilon} \dfrac{(5 \times 2)}{ {5}^{2} }$

$= > f = 9 \times {10}^{9} \times \dfrac{2}{5}$

$= > f = 3.6 \times {10}^{9} newton$

So final answer :

$\boxed{ \sf{ f = 3.6 \times {10}^{9} newton}}$