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Given:
R1 = 10Ω
R2 = 20Ω
V = 3v
To find:
Potential difference across 10Ω resistor.
Solution:
1) The given resistors are in the series so the resultant resistance will be R1 + R2 = 30Ω.
2) According to the ohms law we have,
- V = IR
- 3 = I. 30
- I = 0.1 A
3) As we know that in the series arrangement the current flowing to the resistors will be same at every point.
4) So again by the ohms law the potential difference across 10Ω
- V = IR
- V = 0.1 × 10
- V = 1v
Potential difference across 10Ω resistor = 1 V.
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